It seems to be as far as it can go. at least with the methods used thus far. the characters aren't compatible. Someone mentioned earlier about replacements on this step but I haven't been able to make heads or tails of that clue.
Finally got it... 8-hour-plus solve. For about six of those hours I had Y3c, though I wasn't working on it the whole time.
You could use cryptanalysis to get the keyword; but you won't get the prefix from that - it has to be decoded properly.
I am failing to see what the "4" and "^3" have to do with it, unless it's a vague reference to 4^3=64 as someone said early on in this thread. Of course, this has nothing whatsoever to do with fonts or pixels, and as someone also mentioned base32 early on in this thread, 64 clearly isn't the only relevant number here.
trying to repeat returns mostly unreadable characters. one method returns a valid string of a lower method but trying to input that result ends with the same issue
I will also say this: there are several decoding steps needed to get the final passcode, but each step should leave you with printable ASCII characters. If you get Chinese, you went wrong.
Argh, thanks for this. I actually considered and attempted that solution because of the depth clue, but it didn't work the first time I tried it because I was missing that "a bit different" step.
You can do it fully on mobile, but I used an online Python interpreter to write decoders for any coding I need. At some point it will get difficult to find ready made online tools otherwise.
I used online tools to decode through to Stage 3, but have yet to Profit! from Y3c. Decoding 2->3 appears to be similar to 3->4, except the blocks are shorter (3 vs 4). I suppose if I'd decoded Stage 2 manually I might have learned something similarly relevant?
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It's more of the same, though it doesn't continue the established sequence, as far as I can see. There are some gaps you have to fill in.
You're on the right track. However subsequent steps are somewhat like a map-reduce function.
I see the characters "c" and "E" that repeat. What does this mean?
It means the same thing as the repeated "j" and "F" in the earlier step: redundancy
I've been stuck at Y3c for hours. I'm going crazy
how did you get Y3c? can you do the same once again?
Hurray!!!!!!!!!!!!!!!!!!!!!!!!
clues are hard to come up with for this one ... but you do keep doing what you were doing to get to Y3c, only a bit different
It seems to be as far as it can go. at least with the methods used thus far. the characters aren't compatible. Someone mentioned earlier about replacements on this step but I haven't been able to make heads or tails of that clue.
I just met with JTTW, am I on the right way? whether to continue by repeating again
no more reversals, just repeat
assuming you meant "jJTW..." then yes, but there's a way to go
and it will find me with Y3c as people say?
I was tempted at one point to complain about how useless of a clue this was ... until suddenly it wasn't!
Finally got it... 8-hour-plus solve. For about six of those hours I had Y3c, though I wasn't working on it the whole time.
You could use cryptanalysis to get the keyword; but you won't get the prefix from that - it has to be decoded properly.
I am failing to see what the "4" and "^3" have to do with it, unless it's a vague reference to 4^3=64 as someone said early on in this thread. Of course, this has nothing whatsoever to do with fonts or pixels, and as someone also mentioned base32 early on in this thread, 64 clearly isn't the only relevant number here.
I don't know what I'm doing wrong. I seem to be getting JNFF instead of jJTWF...😭
There are a lot of steps in this puzzle. You seem to have reached an earlier step than discussed by the other people.
trying to repeat returns mostly unreadable characters. one method returns a valid string of a lower method but trying to input that result ends with the same issue
"NJFF" a step towards "jJTWF"
Im stuck there for a while now. Any hint that could unlock my brain?
I think it was hint at base2^n (16, 32, 64).
reverse again to WTN and meet Y3c, 😍
Compare the sequence of "j" and "F" in one string with the "c" and "E" in the next string ... try to figure out why that would be
Trial and error, one piece at a time ... and keep going ... 4, 3, 2, 1
I will also say this: there are several decoding steps needed to get the final passcode, but each step should leave you with printable ASCII characters. If you get Chinese, you went wrong.
I think I've made it to the JNFF/NJFF stage, but I'd like a checksum if that's all right.
Is
==K4====present anywhere in your iteration, or have I befunge'd something up?Argh, thanks for this. I actually considered and attempted that solution because of the depth clue, but it didn't work the first time I tried it because I was missing that "a bit different" step.
Finally got it...😁✌️
Thank for all hint (reverse and convert is the key)
Should i still be following the path of "n2esab" after getting Y3c? Trying to understand how drastic the difference is for the next step =(
You can do it fully on mobile, but I used an online Python interpreter to write decoders for any coding I need. At some point it will get difficult to find ready made online tools otherwise.
Stage 1: NJFF
Stage 2: WTNj
Stage 3: Y3c
Stage 4: ...
Stage 5: Profit!
I used online tools to decode through to Stage 3, but have yet to Profit! from Y3c. Decoding 2->3 appears to be similar to 3->4, except the blocks are shorter (3 vs 4). I suppose if I'd decoded Stage 2 manually I might have learned something similarly relevant?
Step 4 : decode